L = bin1(10, 0.5)->PDF[0:10]
X Input L Output
0 0.0009765625
1 0.009765625
2 0.0439453125
3 0.1171875
4 0.205078125
5 0.24609375
6 0.205078125
7 0.1171875
8 0.0439453125
9 0.009765625
10 0.0009765625


L = bin2(10, 0.8)->PDF[0:10]
X Input L Output
0 1.024E-07
1 4.096E-06
2 7.3728E-05
3 0.000786432
4 0.005505024
5 0.0264241152
6 0.088080384
7 0.201326592
8 0.301989888
9 0.268435456
10 0.1073741824


Evidence for HYPOTHESIS 1: 0.14551915228367

Evidence for HYPOTHESIS 2: 6.8719476736